Question

A scuba diver and her gear displace a volume of 70.0 LL and have a total mass of 74.3 kgkg . what is the buoyant force on the diver in sea water? will the diver sink or float?

Answer 1

The buoyant force on the diver is 703.15 N.

The diver will sink.

Step-by-step explanation:

Given that,

Displace volume = 70.0 L

Total mass = 74.3 kg

We need to calculate the buoyant force on the diver

Using formula of buoyant force

`F_(b)=\rho gV`

Where, V = volume

g = acceleration due to gravity

`\rho`=density of water

Put the value into the formula

`F_(b)=1.025*10^(3)*9.8*70.0*10^(-3)`

`F_(b)=703.15\ N`

We need to calculate the weight of diver

Using formula of weight

`W= mg`

`W=74.3*9.8`

`W=728.14\ N`

As the weight of diver > upthrust force

The diver will sink

Hence, The buoyant force on the diver is 703.15 N.

The diver will sink.

Answer 2

Step-by-step explanation:

Given

Volume displaced by diver
`V=70\ L`

mass of scuba diver
`m=74.3\ kg`

Also density of sea water
`\rho _s=1.025* 10^3\ kg/m^3`

Weight of diver
`W=mg=74.3* 9.8=728.14\ N`

Buoyant force on diver
`F_b=\rho _s* V* g`

`F_b=1025* 70* 10^(-3)* 9.8=703.15\ N`

Since weight is greater than buoyant force so diver will sink in the sea