Question

A small dense ball with mass 1.5 kg is thrown with initial velocity <3, 6, 0> m/s at time t - 0 from a location we choose to call the origin (< 0, 0, 0 > m). Air resistance is negligible. When the ball reaches its maximum height, what is its velocity?

Answer 1

y = 1.84 m , v= ( 3, 0 ,0) m/s

Step-by-step explanation:

This is a projectile launching exercise, at the point of maximum height the vertical speed is zero

`v_(y)`² =
`v_(oy)`² - 2 g y

`v_(y)` = 0

y =
`v_(oy)`² / 2g

The components of the initial velocity are

v₀ₓ = 3 m / s

`v_(oy)` = 6 m / s

Let's calculate

y = 6 2/2 9.8

y = 1.84 m

At this point the speed is only horizontal

v = vox = 3 m / s

v = 3i m/s

v= ( 3, 0 ,0) m/s