Question

you spray your sister with water from a garden hose. the water is supplied to the hose at a rate of 0.649x10-3 m^3/s and the diameter of the nozzle you hold is 5.45x10^-3 m. at what speed does the water exit the nozzle?

Answer 1

27.82 m/s

Step-by-step explanation:

The radius of the hose is half of its diameter

`r = d/2 = 5.45*10^(-3)/2 = 0.002725 m`

So its area must be

`A = \pi r^2 = \pi 0.002725^2 = 2.33*10^(-5) m^2`

The speed of water coming out of the hose is its flow rate divided by the cross-section area of the hose

`v = \dot{V}/A =0.000649 / 2.33*10^(-5) = 27.82 m/s`