Answer:
Step-by-step explanation:
given,
Light wave wavelength in Air, λ_(vac) = 670 nm
wavelength in transparent solid, λ= 420 nm
Refractive index of the solid


n = 1.6
a) speed of light in the solid


v = 0.625 c
b) light's frequency in the solid

frequency of light remain same when light move from one medium to another.
f is the frequency of light

f = 4.47 x 10⁻¹⁴ Hz
the light's frequency in the solid is equal to 4.47 x 10⁻¹⁴ Hz