Question

The block in this illustration is floating in water, which has a density of 1.00 g/cm3 .What is a good estimate of the density of the block if about 30 percent of the block is below water?

Answer 1

Answer : The density of the block is estimated to be,
`0.30g/cm^3`.

Explanation :

Density of the water,
`\rho_w=1.0 g/cm^3`

As we know that,

Buoyant force =
`\rho* volume* g`

where,

g = gravitational acceleration

volume of the block = v

density of the block =
`\rho_o`

Weight of the Block = Buoyant force exerted by water

`\rho_o* v* g=\rho_w* 30\%\text{ of volume of block}* g`

`\rho_o* v* g=\rho_w* 0.30v* g`

`\rho_o* v* 9.8 m/s^2=1 g/cm^3* 0.30v* 9.8 m/s^2`

`\rho_o=0.30 g/cm^3`

Thus, the density of the block is estimated to be,
`0.30g/cm^3`.