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2Na(s) + Cl2(g) ------ 2NaCl(s)

a. What g of NaCl should be produced when 8 moles Na reacts with Cl2?

b. What g of Cl should be produced when 3 moles Na reacts with Cl2?

User Nanomurf
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1 Answer

3 votes

Answer:

1. 7.256g of NaCl

2. 47.33g of Cl2

Step-by-step explanation:

2 moles of Na reacts to produce 2 moles of NaCl

8 moles of Na will still produce 8 moles of NaCl

Mass of NaCl = molar mass of Nacl/moles of Nacl

=58.5/8

=7.256g of NaCl

From the equation, 2 moles of Na reacts with 1 mole of Cl2

3/2 moles of Cl2 will react with 3 moles of Na

Mass of Cl2 = 71/1.5

=47.33g of Cl2

User Maximilian Dietel
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