Question

Three 1.0 kg masses are located at the corners of a vertically standing equilateral triangles with sides 0.80 m long. (a) what is the mutual gravitational potential energy?

Answer 1

gravitational potential energy = -2.50 ×
`10^(-10)` J

Step-by-step explanation:

given data

mass m = 1 kg

length l = 0.80 m

solution

we get here mutual gravitational potential energy that is express as

As Potential energy between two masses =
`(-Gm^2)/(l)` .........1

here is 3 pair of mass so

gravitational potential energy =
`(-3*6.67*10^(-11)*1^2)/(0.80)`

gravitational potential energy = -2.50 ×
`10^(-10)` J