Question

The amplitudes of the displacement and acceleration of an unbalanced motor were measured to be 0.15 mm and 0.6 g, respectively. Determine the speed of the motor . Use g=9.81 m/s^2 .

Answer 1

N=945.76 RPM

Step-by-step explanation:

Given that

A= 0.15 m

Acceleration = 0.6 g

a=0.6 x 9.81 m/s²

a= 5.886 m/s²

We know that acceleration a given as

a = ω² A

ω=Angular speed

`\omega=\sqrt{(0.6* 9.81)/(0.6* 10^(-3))}`

ω=99.04 rad/s

We know that

`\omega=(2\pi N)/(60)\\\\N=(60* \omega)/(2\pi )`

`N=(60* 99.04)/(2\pi )`

N=945.76 RPM

Therefore the speed of the motor will be 945.76 RPM.