Answer:
And if we use two significant figures we have this
![a \approx 6.5 (m)/(s^2)](https://img.qammunity.org/2021/formulas/mathematics/college/ewjavbtsq0lc9bfahlt4whlncqi1gjh8fx.png)
Explanation:
For this case we know that the acceleration is defined by this formula:
![a = (\Delta v)/(\Delta t)](https://img.qammunity.org/2021/formulas/mathematics/college/pa7z3xo2e4wzjdsoygo61nw1h6t29xqga4.png)
Or equivalently:
![a= (v_f -v_i)/(t_f -t_i)](https://img.qammunity.org/2021/formulas/mathematics/college/li077aeyfxa8qt96s3m15m75dwghuhau9b.png)
From the info given we have this:
![\Delta v = v_f -v_i = 5.8 (m)/(s)](https://img.qammunity.org/2021/formulas/mathematics/college/ye526u4eco0jobhny3wzynb7fzllca3c4u.png)
![\Delta t = t_f -t_i = 0.9 s](https://img.qammunity.org/2021/formulas/mathematics/college/xkcwil2jg2vrztpftp9maq70t6hp2wr1rb.png)
And if we replace in the formula we got:
And if we use two significant figures we have this
![a \approx 6.5 (m)/(s^2)](https://img.qammunity.org/2021/formulas/mathematics/college/ewjavbtsq0lc9bfahlt4whlncqi1gjh8fx.png)