Question

a quantity of zinc reacts with sulfuric acid and produces 0.10g of hydrogen. how many particles of zinc are required socratic.org?

Answer 1

grams of zinc required = 3.24 g

Particles of zinc required =
`2.99* 10^(22)`

Step-by-step explanation:

Given that:-

Mass of hydrogen gas produced = 0.10 g

Calculation of the moles of
`H_2` as:-

Mass = 0.10 g

Molar mass of
`H_2` = 2.016 g/mol

The formula for the calculation of moles is shown below:

`moles = (Mass\ taken)/(Molar\ mass)`

Thus,

`Moles= (0.10\ g)/(2.016\ g/mol)`

`Moles= 0.0496\ mol`

According to the reaction shown below:-

`Zn+H_2SO_4\rightarrow ZnSO_4+H_2`

1 mole of hydrogen gas is produced when 1 mole of zinc reacts

So,

0.0496 mole of hydrogen gas is produced when 0.0496 mole of zinc reacts

Moles of Zinc required = 0.0496 moles

Molar mass of zinc = 65.38 g/mol

mass= Moles*Molar mass =
`0.0496\ moles* 65.38\ g/mol=3.24\ g`

Also, 1 mole of Zinc contains
`6.023* 10^(23)` particles

0.0496 mole of Zinc contains
`0.0496* 6.023* 10^(23)` particles

Particles of zinc required =
`2.99* 10^(22)`