Question

If the lily pads are spaced 2.4 m apart and Ferdinand jumps with a speed of 5 m/s taking 0.6 s to go from lily pad to lily pad, at what angle must Ferdinand make each of his jumps?

Answer 1

`36.87^(\circ)`

Step-by-step explanation:

v = Velocity of Ferdinand = 5 m/s

`\theta` = Angle of jump

T = Time taken = 0.6 s

R = Distance between lily pads = 2.4 m

Horizontal range is given by

`R=v_xT\\\Rightarrow R=vcos\theta T\\\Rightarrow cos\theta=(R)/(vT)\\\Rightarrow \theta=cos^(-1)(R)/(vT)\\\Rightarrow \theta=cos^(-1)(2.4)/(5* 0.6)\\\Rightarrow \theta=36.87^(\circ)`

The angle at which Ferdinand make each of his jumps is
`36.87^(\circ)`