Question

What is the magnitude of the momentum of a 3400 kg airplane traveling at a speed of 450 miles per hour?

Answer 1

p=m V

V= 450 mph=0.44*450 meters per second= 198 meters per second

p= 3400*198=673200 kg m/s (in SI units)

Step-by-step explanation:

momentum is the product of mass and the velocity.

unit conversions are done in SI units

Answer 2

The magnitude of momentum of the airplane is
`6.83* 10^5\ kg-m/s`.

Step-by-step explanation:

Given that,

Mass of the airplane, m = 3400 kg

Speed of the airplane, v = 450 miles per hour

Since, 1 mile per hour = 0.44704 m/s

v = 201.16 m/s

We need to find the magnitude of momentum of the airplane. It is given by the product of mas and velocity such that,

`p=mv`

`p=3400\ kg* 201.16 \ m/s`

`p=683944\ kg-m/s`

or

`p=6.83* 10^5\ kg-m/s`

So, the magnitude of momentum of the airplane is
`6.83* 10^5\ kg-m/s`. Hence, this is the required solution.