Question

The magnitude of the electric force between two protons is 2.30 x 10^â26N. How far apart are they?

a. 0.0220 m
b. 0.100 m
c. 0.480 m
d. 0.000570 m
e. 3.10 m

Answer 1

The distance between two protons is 0.1 m

Step-by-step explanation:

Given that,

The magnitude of force between two protons is,
`F=2.3* 10^(-26)\ N`

We know that the charge on proton is,
`q_1=q_2=1.6* 10^(-19)\ C`

If F is the electric force between two charges. It is given by the electrostatic force of attraction of repulsion. It is given by :

`F=(kq_1q_2)/(d^2)`

d is the distance between charges

`d=\sqrt{(kq^2)/(F)}`

`d=\sqrt{(9* 10^9* (1.6* 10^(-19))^2)/(2.3* 10^(-26))}`

d = 0.1 m

So, the distance between two protons is 0.1 m. Hence, this is the required solution.