Question

1. Determine the number of atoms in 4.64 g gold.

2. Calculate the mass of 4.12 10e24 molecules of glucose (C6H12O6).

Answer 1

The answer to your question is below

Step-by-step explanation:

1.-

a) Look for the mass number of Gold in the periodic table

Mass number = 197 g

Use proportions to answer this question

197 g of gold ------------- 6.023 x 10 ²³ atoms

4.64 g of gold ---------- x

x = (4.64 x 6.023 x 10²³) / 197

x = 1.42 x 10²² atoms

2.- mass of 4.12 x 10²⁴ molecules of glucose

Molecular mass = (6 x 12) + (12 X 1) + (6 x 16)

= 72 + 12 + 96

= 180 g

180 g of glucose ------------------- 6.023 x 10 ²³ molecules

x ------------------- 4.12 x 10 ²⁴ molecules

x = (4.12 x 10²⁴ x 180) / 6.023 x 10²³

x = 1231.3 g of glucose