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By calculating |AC| and |BC| , show that |AC| =|BC|​

By calculating |AC| and |BC| , show that |AC| =|BC|​-example-1
User BumMo Koo
by
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1 Answer

2 votes

Answer:


|AC| = |BC| = √(29)

Explanation:

We are given the coordinates of points A, B, and C.

A(3, 1)

B(0, 4)

C(-2, -1)

Now we use the distance formula to find each length.


d = √((x2 - x_1)^2 + (y_2 - y_1)^2)


|AC| = √((-2 - 3)^2 + (-1 - 1)^2)


|AC| = √((-5)^2 + (-2)^2)


|AC| = √(25 + 4)


|AC| = √(29)


|BC| = √((-2 - 0)^2 + (-1 - 4)^2)


|BC| = √((-2)^2 + (-5)^2)


|BC| = √(4 + 25)


|BC| = √(29)


|AC| = |BC| = √(29)

User Johnny Everson
by
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