Question

How to turn this equation:
y= -1.02(x-3)^2+9.25
into factored form

Answer 1

`y=(102x-306-5√(3774))(102x-306+5√(3774))`

Explanation:

You first equate it to zero to get:

`-1.02(x-3)^2+9.25=0`

Then solve using square root method

`-1.02(x-3)^2=-9.25`

`(x-3)^2=(-9.25)/(-1.02)`

`(x-3)^2=(925)/(102)`

`x=3\pm\sqrt{(925)/(102)}`

Or

`x=3\pm{(5√(3774))/(102)}`

`x={(306\pm5√(3774))/(102)}`

Now work it backwards

`102x-(306\pm5√(3774))=0`

`(102x-306-5√(3774))(102x-306+5√(3774))=0`

Hence the factored form is:

`y=(102x-306-5√(3774))(102x-306+5√(3774))`