Question

A balloon has a volume of 1.2 L at a pressure of 1.1 atm and a temperature of 25°C. If the temperature changes to 75ºC and the volume changes to 6.7 L, what is the new pressure?​

Answer 1

P₂ = 0.23 atm

Step-by-step explanation:

Given data:

Initial volume = 1.2 L

Initial pressure = 1.1 atm

Initial temperature = 25 °C (25 +273 = 298 K)

Final temperature = 75°C(75+273 = 348 K)

Final volume = 6.7 L

Final pressure = ?

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₂ = P₁V₁ T₂/ T₁ V₂

P₂ = 1.1 atm × 1.2 L × 348 K / 298 K × 6.7 L

P₂ = 459.36 atm .L. K / 1996.6 k.L

P₂ = 0.23 atm