Question

The equation Y-5=6(x+1) is written in point-slope form. What is the equation written in slope-intercept form?

y = kx + 11
y = 3x - 1
y = x - 4
y = 5x + 6

Answer 1

The first choice, y=kx*11, should be the answer.

Slope intercept form can be shown as y=Mx+b. Do tho this first you want to distribute on the left side of the equation so that you get y-5=6x+6. Next you want to add by 5 on both sides to isolate y which will give you y=6x+11

Answer 2

`y = k x +11`

Explanation:

Point-slope form:-

step1:-

The standard of point - slope form is
`y-y_(1) = m (x-x_(1)`

Give equation is Y-5=6(x+1)

simplification is
`y=5+6 x+6`

`y = 6 x+11`

This is the form of slope-intercept form

`y=m x+c`

here m is the slope of the line

and y - intercept is c

so m=6 and y- intercept is 11

Step 2:-

Given option
`y = k x +11`

here the y- intercept is 11

so final answer is
`y = k x +11`