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Question 30

1 pts
What is the angular diameter to the nearest hundredth of a degree of a
spherical object with a diameter of 16 m at a distance of 1338 m?
O 0.09 degrees
6.28 degrees
O 0.21 degrees
O
1.24 degrees
O 0.69 degrees

1 Answer

2 votes

Answer:
0.69\°

Step-by-step explanation:

The angular diameter
\delta of a spherical object is given by the following formula:


\delta=2 sin^(-1)((d)/(2D))

Where:


d=16 m is the actual diameter


D=1338 m is the distance to the spherical object

Hence:


\delta=2 sin^(-1)((16 m)/(2(1338 m)))


\delta=0.685\° \approx 0.69\° This is the angular diameter

User Jops
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