Question

JKLM is a parallelogram.
Find m

Answer 1

m∡L = 51°

Explanation:

In any parallelogram, the sum of the angle measures on one side is 180°.

Therefore we have the equation:

`(2z-3)^o+(5z-6)^o=180^o`

Let's skip the degree marks and parentheses

`2z-3+5z-6=180` combine like terms

`(2z+5z)+(-3-6)=180`

`7z-9=180` add 9 to both sides

`7z-9+9=180+9`

`7z=189` divide both sides by 7

`(7z)/(7)=(189)/(7)`

`z=27`

Put the value of z to the expression m∡L = (2z - 3)°:

`m\angle L=(2\cdot27-3)^o=(54-3)^o=51^o`

Answer 2

Good evening ,

Answer:

m∠L = 51°

Explanation:

the sum of measures of angles of a parallelogram = 360°

2[(2z-3)+(5z-6)] = 360

⇔ 2[7z - 9] = 360 ⇔ 14z - 18 = 360 ⇔ 14z = 378 ⇔ z = 27

m∠L = 2z - 3 = 2(27) - 3 = 54 - 3 = 51.

:)