Question

Idently the graph of f(x) = 3(x - 1) - 4. Then identity the vertex and ads of symmetry find the minimum value of and describe where the function is increasing and decreasing

С
.
The vertex of the parabola is (0)
The axis of symmetry is x = 0
The minimum value is
The function is decreasing to the
oft
The function is increasing to the

Answer 1

See below

Explanation:

I assume you mean
`f(x) = 3(x-1)^2-4`

The equation is already in vertex form
`f(x)=a(x-h)^2+k` where
`a` affects how "fat" or "skinny" the parabola is and
`(h,k)` is the vertex. Therefore, the vertex is
`(h,k)\rightarrow(1,-4)`.

The axis of symmetry is a line where the parabola is cut into two congruent halves. This is defined as
`x=h` for a parabola with a vertical axis. Hence, the axis of symmetry is
`x=1`.

The minimum value is the smallest value in the range of the function. In the case of a parabola, the y-coordinate of the vertex is the minimum value. Therefore, the minimum value is
`y=-4`.

The interval where the function is decreasing is
`(-\infty,1)`

The interval where the function is increasing is
`(1,\infty)`