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Find the value of x an y such that :
Y = y² (x²-3)
Y = 6

User Stj
by
6.9k points

1 Answer

1 vote

We know
y=6 which means we already have one solution.

Plug in 6 in the first equation where y-terms are and solve for x.


</p><p>6=6^2(x^2-3) \\</p><p>1=6(x^2-3) \\</p><p>1=6x^2-18 \\</p><p>6x^2=19 \\</p><p>x^2=(19)/(6) \\</p><p>x_(1,2)=\boxed{\pm\sqrt{(19)/(6)}}</p><p>

Hope this helps.

User Klenium
by
7.4k points