Question

19. A silver statue of Pooja is leaning against a wall. The top of her head

touches the wall at 40 feet. If the base of the statue is 9 feet away from the
wall, how tall is Pooja’s statue, in feet?

Answer 1

Answer:
`41\ feet`

Explanation:

You need to draw a right triangle.

Observe the right triangle attached, where "x" is the height in feet of Pooja’s statue.

You need to use the Pythagorean Theorem. This is:

`a^2=b^2+c^2`

Where "a" is the hypotenuse and "b" and "c" are the legs of the right triangle.

In this case you can identify that:

`a=x\\b=40\\c=9`

Therefore, you can substitute values into
`a^2=b^2+c^2`:

`x^2=40^2+9^2`

Finally, you must solve for "x" in order to find its value.

You get that this is:

`x=√(40^2+9^2)\\\\x=41`