Question

Use technology or a z-score table to answer the question.

The scores for a golf tournament are normally distributed with a mean of 210 and a standard
deviation of 80. Ella scored 230 at the tournament
What percent of golfers scored less than Ella?
Round your answer to the nearest whole number

A:60%
B:75%
C:77%
D:80%

Answer 1

Answer: A:60%

Explanation:

Since the scores for a golf tournament are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = scores for the tournament.

µ = mean score

σ = standard deviation

From the information given,

µ = 210

σ = 80

We want to find the probability percent of golfers that scored less than Ella. It is expressed as

P(x < 230)

z = (230 - 210)/80 = 0.25

Looking at the normal distribution table, the probability corresponding to the z score is 0.5987

Therefore, the percent of golfers that scored less than Ella is

0.5987 × 100 = 59.87

Approximately 60%