Question

In air an object weighs 15N. when immersed in water it weighs 12N . when immersed in another liquid it weighs 13N . determine the density of d object and that of d other liquid​

Answer 1

Its volume displaced 3 Newtons of water

3 Newtons = mass of water * g

g is about 9.81m/s^2

so mass of water =3/9.81 =0.306 kg

Water density is about 1000 kg/meter^3

0.306 kg * 10^-3m^3/kg = 3.06 *10^-4 m^3 volume

so

15 kg/3.06*10^-4 m^3 = 4.9*10^4 kg/m^3

if you want grams/cm^3

4.9*10^4 * 10^-6 m^3/cm^3 * 10^3 g/kg =49 g/cm^3

Answer 2

Answer: relative density of object=5 relative density of liquid=2/3

Step-by-step explanation:

Loss of weight in water=15-12=3

Density of object=weight in air÷weight in water

Density of object=15÷3=5

Density of liquid=upthrust in liquid÷upthrust in water

Density of liquid=(15-13)÷(15-12)=2/3