163k views
3 votes
From 7x2+5xy−3y2 subtract the sum of 2x2+3xy−5y2 and x2−7xy−4y2.

User Aleshia
by
6.8k points

1 Answer

1 vote

Answer:
4x^(2) +9xy+6y^(2)

Explanation:

First equation
=
2 x^(2) +3xy-5y^(2)

Second equation
=
x^(2) -7xy-4y^(2)

Third equation
=
7x^(2) +5xy-3y^(2)
3x^(2) -4xy-9y^(2)

Sum of the following of two valuable equation first and second


(2x^(2) +3xy-5y^(2) ) + (x^(2) -7xy-4y^(2) )


(2+1) x^(2) +(3-7)xy+(-5-4)y^(2)


3x^(2) -4xy-9y^(2)

Subtract third equation from the sum of two valuable expression


(7x^(2) +5xy-3y^(2) ) - (3x^(2) -4xy-9y^(2) )


(7-3)x^(2) +(5-(-4))xy +(-3-(-9))y^(2)


4x^(2) +9xy+6y^(2)

User Lior Frenkel
by
6.0k points