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If f(×)=3×^2 and g(×)=4×^3+1, what is the degree of (f°g)(×)​

1 Answer

6 votes

Answer: The degree is 6

Explanation:

g(x) = 4x^3 + 1

f(x) = 3x^2

Now,

(f°g)(x)

f( 4x^3 + 1 )

4(3x^2)^3 + 1

4×27×x^6 + 1

108x^6 + 1

So, the degree of x is 6

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