Question

Evaluate any two x-values (between -5 and 5) into AJ's function. Show your work. How does your work prove that AJ made a mistake in the graph?

AJ graphs the function f(x) = -(x + 2)^2 - 1 as shown below.

Answer 1

See explanation

Explanation:

The function AJ graphed is
`f(x)=-(x+2)^2-1`.

When x=0, we get
`f(0)=-(0+2)^2-1`

This implies
`f(0)=-4-1=-5`

When x=1
`f(1)=-(1+2)^2-1=-3^2-1=-9-1=-10`

All the values we evaluated between -5 and 5 gives negative value.

This means that AJ's graph should have turn upside down