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3 votes
Which of the following is the correct relationship among the acceleration, velocity, and position?

1. ads = vdv
2. adv = sds
3. vda = sds
4. sda = vdv

User Soju Tom
by
4.2k points

2 Answers

5 votes

Answer:

option (1)

Step-by-step explanation:

Acceleration is defined as the rate of change of velocity with respect to time.

a = dv / dt

where, dv is the change in velocity and dt is the change in time.

So,
a = (dv)/(dt)* (ds)/(ds)


a = (dv)/(ds)* (ds)/(dt)

So, a ds = v dv

Thus, option (1) is correct.

User Ginsberg
by
4.9k points
2 votes

Answer:1

Step-by-step explanation:

If

s=displacement

v=velocity of particle

a=acceleration of particle

acceleration can be written as rate of change of velocity

so
a=\frac{\mathrm{d} v}{\mathrm{d} t}

multiply and divide by
ds


a=\frac{\mathrm{d} v}{\mathrm{d} t}* (ds)/(ds)


a=\frac{\mathrm{d} v}{\mathrm{d} s}* \frac{\mathrm{d} s}{\mathrm{d} t}


a=v\frac{\mathrm{d} v}{\mathrm{d} s}


ads=vdv

option 1 is correct

User Weston
by
3.9k points