Answer: The temperature in the pressure cooker set on high is 206.14°C
Step-by-step explanation:
STP conditions:
Pressure = 14.7 psi
Temperature = 273 K
To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,
![(P_1)/(T_1)=(P_2)/(T_2)](https://img.qammunity.org/2021/formulas/chemistry/high-school/djlfnlyy5uburbey6vx6jwso32aea28a9w.png)
where,
are the initial pressure and temperature of the gas.
are the final pressure and temperature of the gas.
We are given:
![P_1=14.7psi\\T_1=273K\\P_2=(14.7+11.1)psi=25.8psi\\T_2=?](https://img.qammunity.org/2021/formulas/chemistry/high-school/ab739emuigtdpmbjsl4bavku0qahscxm3o.png)
Putting values in above equation, we get:
![(14.7psi)/(273K)=(25.8psi)/(T_2)\\\\T_2=(25.8* 273)/(14.7)=479.14K](https://img.qammunity.org/2021/formulas/chemistry/high-school/sm95894w1si2xhsyquger35x42mi12klc9.png)
Converting the temperature from kelvins to degree Celsius, by using the conversion factor:
![T(K)=T(^oC)+273](https://img.qammunity.org/2021/formulas/chemistry/high-school/iycx4ao3dr9yes7un0vlvxteuywi6wkf53.png)
![479.14=T(^oC)+273\\\\T(^oC)=(479.14-273)=206.14^oC](https://img.qammunity.org/2021/formulas/chemistry/high-school/5symg4ctoaxot1qqmrp7fd1mbrlfyl9be6.png)
Hence, the temperature in the pressure cooker set on high is 206.14°C