Answer:
The answer to your question is pH = 4
Step-by-step explanation:
Data
Volume 1 = V1 = 1 ml = 0.001 l
Concentration 1 = C1 = 0.1 M
Volume 2 = V2 = 1 l
Concentration 2 = C2 = ?
Process
1.- Find the new concentration of the solution
C₁V₂ = C₂V₂
Solve for C₂
C₂ = C₁V₁ / V₂
Substitution
C₂ = (0.1 x 0.001) / 1
Result
C₂ = 0.0001 M
2.- Find the pH of the solution
Formula
pH = -log[H⁺]
Substitution
pH = - log[0.0001]
Simplification
pH = 4