Answer:
The Option is D) ΔDEC ≅ ΔDEA
ΔDEC ≅ ΔDEA ….{By Side-Angle-Side Congruence Statement}
Explanation:
Given:
AE ≅ EC
∠AED ≅ ∠CED = 90°
To Prove:
ΔDEC ≅ ΔDEA
Proof:
In ΔDEC and ΔDEA
AE ≅ EC ……….{Given}
∠AED ≅ ∠CED …………..{measure of each angle is 90°}
ED ≅ ED ……….{Reflexive Property}
ΔDEC ≅ ΔDEA ….{By Side-Angle-Side Congruence Statement}