Question

a) A fashionable spike heel has an area of 0.878 cm2. When a 61.4 kg woman walking in this shoe sets her full weight down on the heel, what is the pressure ?

Answer 1

Step-by-step explanation:

Answer:

6853.3 Pa

Step-by-step explanation:

Area, A = 0.878 cm² = 0.0878 m²

mass, m = 61.4 kg

Force, F = m x g = 61.4 x 9.8 = 601.72 N

Pressure = force / Area

Pressure, P = 601.72 / 0.0878

P = 6853.3 Pa

Thus, the pressure is 6853.3 Pa.

P = 61.4 x 9.8 / 0.878

Answer 2

Pressure,
`P=6.85* 10^5\ Pa`

Step-by-step explanation:

Given that,

Area of the heel,
`A=0.878\ cm^2=0.878* 10^(-4)\ m^2`

Mass of the woman, m = 61.4 kg

To find,

Pressure on the heel.

Solution,

The pressure acting on the heel is given by the net force acting on the box per unit area. Its formula is given by :

`P=(F)/(A)`

`P=(mg)/(A)`

`P=(61.4* 9.8)/(0.878* 10^(-4))`

`P=6.85* 10^5\ Pa`

So, the pressure exerted by the heel of the woman is
`6.85* 10^5\ Pa`. Hence, this is the required solution.