Question

David measured the height of a window frame as 5.61 feet, but the actual height was 6 feet. What is the percentage of error in David's measurement?

Answer 1

Percentage of error in David's measurement is 6.5 %

Explanation:

Measured height = 5.61 feet

Original height = 6 feet

Error in measurement = Original height - Measured height

Error in measurement = 6 - 5.61

Error in measurement = 0.39 feet

`\texttt{Percentage of error in David's measurement = }\frac{\texttt{Error in measurement}}{\texttt{Original height}}* 100\\\\\texttt{Percentage of error in David's measurement = }(0.39)/(6)* 100\\\\\texttt{Percentage of error in David's measurement = }6.5\%`

Percentage of error in David's measurement is 6.5 %