146k views
1 vote
The daily production of carbon dioxide from an 880 MW coal-fired power plant is estimated to be 31,000 tons. A proposal has been made to capture and sequester the CO2 at approximately 300 K and 140 atm. At these conditions, the specific volume of CO2 is estimated to be 0.012 m3/kg. What volume (m3) of CO2 would be collected during a one-year period?

User Merad
by
5.1k points

1 Answer

4 votes

Answer:


1.3578* 10^(8) m^3 volume of carbon dioxide gas would be collected during a one-year period.

Step-by-step explanation:

Mass of carbon dioxide gas collected in a day = 31,000 Tonn

1 Tonn = 1000 kilogram

31,000 Tonn =
31,000* 1000 kg=31,000,000 kg

Specific volume of the carbon dioxide gas =
V_s


V_s=0.012 m^3/kg

Volume of carbon dioxide gas collected in a day = V


V=V_s* 31,000,000 kg=0.012 m^3/kg* 31,000,000


V=372,000 m^3

1 year = 365 days

Volume of carbon dioxide gas collected in a year = V'


V'=372,000* 365 m^3=1.3578* 10^(8) m^3


1.3578* 10^(8) m^3 volume of carbon dioxide gas would be collected during a one-year period.

User Parand
by
4.0k points