Velocity of the boat with respect to Earth is 5 m/s 56.31° north of east
Step-by-step explanation:
A boat heads north in still water at 4.5 m/s directly across a river that is running east at 3.0 m/s.
Let north be positive y axis and east be positive x axis.
We have
Velocity of boat = 4.5 j m/s
Velocity of river = 3 i m/s
Velocity of the boat with respect to Earth = 3 i + 4.5 j
![\texttt{Magnitude of velocity = }√(3^2+4.5^2)\\\\\texttt{Magnitude of velocity = }5.41m/s](https://img.qammunity.org/2021/formulas/physics/high-school/idmuja4vawiodj25nutxnhge37xbipwmfh.png)
![\texttt{Angle = }tan^(-1)\left ( (4.5)/(3)\right )\\\\\texttt{Angle = }56.31^0](https://img.qammunity.org/2021/formulas/physics/high-school/xmksaz5rhma1yk5tpyuvk4r3o7tzyrh6zs.png)
That is 56.31° north of east.
Velocity of the boat with respect to Earth is 5 m/s 56.31° north of east