Question

You are flying a kite. You have let out 28 feet of string. If the angle that the kite’s string makes with the ground is 52°, how high above the ground is the kite? Round to the nearest foot. You must show your work to receive credit.

Answer 1

Height
`=22\ feet`

Explanation:

Let Kite is at point
`Q` and My place is
`P`.

`PQ=length\ of\ string=28\ feet`

Let
`RQ` be height and it is
`=h\ feet`

`\angle QPR=52\textdegree`

`Now\ in\ \triangle PQR\\\\\sin \angle QPR=(Opposite)/(Hypotenuse)=(QR)/(PQ)\\\\\sin 52=(h)/(28)\\\\h=28* \sin 52\\\\h=28* 0.7880\\\\h=22.064\approx 22\ feet`