Answer:
Step-by-step explanation:
spring constant, K = 13.1 N/m
22 oscillations in 20 seconds
time taken to complete one oscillation is called time period.
T = 20 / 22 second = 0.909 seconds
(a) let m be the mass.
The formula for the time period is
![T = 2\pi \sqrt{(m)/(K)}](https://img.qammunity.org/2021/formulas/physics/high-school/dyeefpais6gajagq8s06gfp5rm5xs9zreu.png)
![m = (T^(2)K)/(4\pi ^(2))](https://img.qammunity.org/2021/formulas/physics/high-school/xst5agizg3sm8jmxn0day8xeyn25848q1t.png)
![m = (0.909^(2)* 13.1)/(4\pi ^(2))](https://img.qammunity.org/2021/formulas/physics/high-school/s65bgsu3ieafxjpcq82a1hhfftck5wmhm6.png)
m = 0.275 kg
(b) maximum speed, v = ω A = 2π A / T
v = ( 2 x 31.4 x 0.1) / 0.909
v = 0.691 m/s