Answer:
And the 90% confidence interval would be given (0.4542;0.5105).
So the correct option is:
B. 0.4542 to 0.5105
Explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The population proportion have the following distribution
Solution to the problem
For this case the estimated proportion is given by:

The confidence interval would be given by this formula
For the 90% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the normal standard distribution.
And replacing into the confidence interval formula we got:
And the 90% confidence interval would be given (0.4542;0.5105).
So the correct option is:
B. 0.4542 to 0.5105