Question

For each release height, a gate was located at half the release height. Explain why the bob does not appear to have half of its maximum speed at this point.

Answer 1

`Em_(f)` = √2

Step-by-step explanation:

Let's use the law of conservation of energy, to find the speed at medium height

Starting point Higher

Em₀ = U = m g y

Final point. Lower

`Em_(f)` = K = 1/2 m v²

Em₀ =
`Em_(f)`

mg y = ½ m v²

v = √ 2g y

For the average height y = h / 2

v = √ 2 g h / 2 = (√ 2gh) √ ½

Let's divide the two relationships

v / v_media = √ mgh / (√ mgh / √2)

v / v_medio = √2

From here we see that the speed is lower