Question

What is an equations of the line that passes through the points (2,2) and (-2,8)

Answer 1

Explanation:

points (2,2) and (-2,8)

y2 = 8, y1 = 2, x2 = -2, x1 = 2

Slope m = (y2 - y1)/(x2 - x1)

m = (8 - 2)/(-2 - 2)

m = 6/-4

m = -3/2

The equation of line

y - y1 = m(x - x1)

y - 2 = -3/2(x - 2)

y - 2 = -3x/2 + 3

y = -3x/2 + 3 + 2

y = -3x/2 + 5