Answer:
The strength of the electric field on the point charge at this distance is 4000 N.
Step-by-step explanation:
The electric field strength is determined using the formula
![E=(kQ)/(d^(2) )](https://img.qammunity.org/2021/formulas/physics/middle-school/hxjosp4evpa5pnq7c3dm2no8g186zqevyb.png)
Thus, field strength is directly proportional to the charge of the charge and inversely proportional to the square of the distance between them. In the above equation, Q is the charge and d is the distance, k is the constant 9×
![10^(9)](https://img.qammunity.org/2021/formulas/physics/middle-school/220tqjqkf0bnfsuf36ufepwqxogiq0szvb.png)
So, the electric field strength will be
![E=(9*10^(9) *4*10^(-6) )/(9)=4*10^(3) =4000 N](https://img.qammunity.org/2021/formulas/physics/middle-school/wbmlnf9nl71mbs522a7gvhok8qy4lcyssi.png)
So the electric field strength is 4000 N.