1 Answer

Blaszard · Answer 1 · 2021-09-06T13:24:42+0000

Answer:

10.34 m/s^2

Step-by-step explanation:

length, L = 1.07 m

Time period, T = 2.02 s

The formula of the time period of the pendulum is

$T = 2\pi \sqrt{(L)/(g)}$

where, g is the free fall acceleration on that planet.

$g=4\pi ^(2)(L)/(T^(2))$

$g=4\pi ^(2)(1.07)/(2.02^(2))$

g = 10.34 m/s^2

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