Answer:
Step-by-step explanation:
mass of truck, m = 2100 kg
initial velocity, u = 32 km/h north = 8.89 m/s
final velocity, v = 45 km/h east = 12.5 m/s
(a) Initial kinetic energy, Ki = 1/2 m u²
Ki = 0.5 x 2100 x 8.89 x 8.89 = 82983.71 J
Final kinetic energy, Kf = 1/2 mv²
Kf = 0.5 x 2100 x 12.5 x 12.5 = 164062.5 J
(b)
Write the velocities in vector form


Change in momentum = m (v - u)
p = 2100 (12.5 i - 8.89 j ) = 26250 i - 18669 j
Magnitude of change in momentum

p = 32211.71 kg m/s
(c)

θ = 35.4 degree