Answer : The pKa for acetic acid is, 4.76
Explanation : Given,

Concentration of acetic acid (acid) = 0.10 M
Concentration of sodium acetate (salt) = 0.10 M
The equilibrium reaction will be:

Using Henderson Hesselbach equation :
![pH=pK_a+\log ([Salt])/([Acid])](https://img.qammunity.org/2021/formulas/biology/college/z944fnahhldpjolfrvealc6q9baj5h69q3.png)
![pH=pK_a+\log ([CH_3COONa])/([CH_3COOH])](https://img.qammunity.org/2021/formulas/biology/college/9z631uckelzflaezrc143zx3jy64v38e5f.png)
Now put all the given values in this expression, we get:


Therefore, the pKa for acetic acid is, 4.76