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Suppose that we are testing H0 : 0 versus H1 : 0 with a sample size of n 10. Calculate bounds on the P-value for the following observed values of the test statistic:

1 Answer

4 votes

Answer:

a)
p_V = 2*P(t_(9) >|2.48|) =0.0349

We can use the following excel code: "=2*(1-T.DIST(2.48,9,TRUE))"


0.03 < p_v <0.04

b)
p_V = 2*P(t_(9) >|-3.95|)=0.003355

We can use the following excel code: "=2*(1-T.DIST(3.95,9,TRUE))"


p_v <0.01

c)
p_V = 2*P(t_(9) >|2.69|) =0.02480

We can use the following excel code: "=2*(1-T.DIST(2.69,9,TRUE))"


0.01 < p_v <0.03

d)
p_V = 2*P(t_(9) >|1.88|) =0.09281

We can use the following excel code: "=2*(1-T.DIST(1.88,9,TRUE))"


0.05 < p_v <0.1

Explanation:

For this case we are testing the following system of hypothesis:

Null hypothesis:
\mu =0

Alternative hypothesis:
\mu \\eq 0

The sample size is n=10, so then the degrees of freedom are given by:


df=n-1= 10-1=9

In order to calculate the p value we can use the fact that we are conducting a bilateral test so then the p value is given by:


p_V = 2*P(t_(9) >|t_0|)

Where
t_0 represent the calculated or observed statistic.

a) t0= 2.48


p_V = 2*P(t_(9) >|2.48|) =0.0349

We can use the following excel code: "=2*(1-T.DIST(2.48,9,TRUE))"


0.03 < p_v <0.04

b) t0= -3.95


p_V = 2*P(t_(9) >|-3.95|)=0.003355

We can use the following excel code: "=2*(1-T.DIST(3.95,9,TRUE))"


p_v <0.01

c) t0=2.69


p_V = 2*P(t_(9) >|2.69|) =0.02480

We can use the following excel code: "=2*(1-T.DIST(2.69,9,TRUE))"


0.01 < p_v <0.03

d) t0=1.88


p_V = 2*P(t_(9) >|1.88|) =0.09281

We can use the following excel code: "=2*(1-T.DIST(1.88,9,TRUE))"


0.05 < p_v <0.1

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