Question

What is the limiting reactant in

2K + F2 = 2KF


If you have 10 molecules of K and 10 molecules of F2?

Answer 1

The limiting reactant is the K

Step-by-step explanation:

This is the reaction:

2 K + F₂ → 2KF

2 moles of potassium react with 1 mol of fluorine

Let's determine the moles:

6.02x10²³ molecules are contained in 1 mol

10 molecules are contained in (10 . 1) / NA = 1.66x10⁻²³ moles

For 1 mol of flourine, we need 2 moles of K

If we have 1.66x10⁻²³ moles of Fl₂, we will need the double of K

For 2 moles of K, we need 1 mol of Fl₂

If we have 1.66x10⁻²³ moles of K, we will need the half of Fl₂

Then, the limiting reactant is the K