Question

Graph the linear equation and answer each of the following questions. y=-2x-3

What is the y-intercept?
What is the slope (in fraction form)?
Is your slope positive or negative?
Explain how you plotted your second point.
Please use the graph I have here I need the same exact one.

Answer 1

Part 1) The y-intercept is the point (0,-3)

Part 2) The slope in fraction form is
`m=-(2)/(1)`

Part 3) The graph in the attached figure

Explanation:

we have

`y=-2x-3`

Part 1) What is the y-intercept?

Remember that

The y-intercept is the value of y when the value of x is equal to zero

so

For x=0

substitute in the linear equation and solve for y

`y=-2(0)-3\\y=-3`

The y-intercept is the point (0,-3)

Part 2) What is the slope (in fraction form)?

we have

`y=-2x-3`

This is the equation of the line in slope intercept form

`y=mx+b`

where

m is the slope or unit rate

b is the y-intercept

so

`m=-2`

In fraction form is

`m=-(2)/(1)`

The slope is negative, that means, is a decreasing function (as the x-values increases the y-values decreases)

Part 3) Graph the line

To graph the line we need two points

From the y-intercept (0,-3) use the slope to find your next point

The slope is -2, so you will rise -2 (2 units down) and run 1 (1 unit to the right).

The next point is (0+1,-3-2) -----> (1,-5)

so

Plot the points (0,-3) and (1,-5), connect them and graph the line

The graph in the attached figure