Question

A 10-V battery supplies a constant current of 0.5 amp to a resistance for 30 min.

(a) Determine the resistance, in ohms.

(b) For the battery, determine the amount of energy transfer by work, in kJ.

Answer 1

a)R=20 ohm

b)W= 9 KJ

Step-by-step explanation:

Given that

Voltage difference ,ΔV= 10 V

Current ,I = 0.5 A

Resistance = R

time = 30 min = 30 x 60 s = 1800 s

a)

We know that

ΔV= I R

`R=(10)/(0.5)\ ohm`

R=20 ohm

b)

The power P = V I

P = 10 x 0.5 = 5 Watt ( 1 watt = J/s)

We know that

`P=(W)/(t)`

W=work

t=time

W = P t

W= 5 x 1800 J

W= 9000 J =9 KJ

W= 9 KJ