Answer:
The height h of this right triangle is 57.74±1.74ft.
Step-by-step explanation:
Knowing that this is a right triangle, if one of the angles adjacent to the base, θ is 30º, the other angle is 90º. Therefore we can calculate the height h can be calculated with the tangent:

For the uncertainty we use the partial derivatives:

We have to be careful to use Δθ in radians:
